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For three-phase AC, use line-to-line voltage and line current. The tool applies the corresponding circuit multiplier.
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Compare the resistance-related voltage drop of different conductor sizes and cable lengths for a stated load current.
For three-phase AC, use line-to-line voltage and line current. The tool applies the corresponding circuit multiplier.
Use one-way length and the cross-sectional area of one conductor. Set the expected conductor temperature.
Read volts and percent of supply. For AC, assess the omitted reactance and starting conditions separately.
40 A, 100 m one-way length, 16 mm² copper, 70 °C conductor temperature and 0.85 power factor.
Estimated resistive drop is about 7.593 V, or 1.898% of the 400 V supply.
Higher conductor temperature raises the assumed resistance.
Larger conductor area lowers the resistive drop at the same current and length.
AC reactance, harmonics, starting current, cable ampacity and protection coordination are outside the model.
Doubling the cable route length manually for a two-wire circuit; the formula already includes the return path.
R_conductor = ρ20[1 + α(T − 20)] L / A
DC: ΔV = 2 I R; single-phase AC: ΔV ≈ 2 I R cos φ
Balanced three-phase AC: ΔV ≈ √3 I R cos φ
It estimates one voltage-drop component. Ampacity, installation method, short-circuit withstand, protection and applicable drop limits need separate assessment.
The real cable has reactance and may have unbalanced current or other effects omitted by this resistance-only approximation.